Miss Lee teaches a mini lesson on the area of parallelograms, explaining that the formula for the area is the same as that of a rectangle: base times height. She emphasizes the importance of using the perpendicular height, not the slanted sides. The lesson includes two practice problems: one calculating the area of a region under a thunderstorm warning and another finding the height of a parallelogram given its area and base.

What is the main topic of Miss Lee's lesson?

• The area of triangles

• The perimeter of rectangles

• The area of parallelograms

• The volume of cubes

How is the area of a parallelogram related to the area of a rectangle?

• It is unrelated to the area of a rectangle

• It is double the area of a rectangle

• It is the same as the area of a rectangle

• It is half the area of a rectangle

What is crucial about the height in the formula for the area of a parallelogram?

• It must be equal to the base

• It must be perpendicular to the base

• It must be parallel to the base

• It must be longer than the base

What is the formula for the area of a parallelogram?

• Base divided by height

• Base times height

• Base plus height

• Base minus height

Why is it important to use the perpendicular height in the area formula?

• It makes the calculation easier

• It is a traditional method

• It is a requirement for all shapes

• It ensures the area is calculated correctly

In the first practice problem, what is the base of the parallelogram?

• 21 miles

• 15.5 miles

• 10 miles

• 20 miles

What is the area of the region under the thunderstorm warning in Practice Problem 1?

• 300 square miles

• 325.5 square miles

• 315 square miles

• 350 square miles

In Practice Problem 2, what is the given base of the parallelogram?

• 20 inches

• 12 inches

• 15 inches

• 10 inches

What is the area of the parallelogram in Practice Problem 2?

• 312 square inches

• 320 square inches

• 315 square inches

• 300 square inches

How do you find the height in Practice Problem 2?

• Multiply the base by the area

• Divide the area by the base

• Subtract the base from the area

• Add the base and the area