Water Temperature and Heat Transfer

The video tutorial explains a problem involving mixing two water samples with different temperatures. The goal is to determine how much water the lab partner added to the initial 90 mL of water at 58.0°C, given the final temperature of the mixture is 69.0°C. The density of water is assumed to be 1 gram per mL. The tutorial walks through the process of calculating the heat transfer for the known water sample and using that information to find the mass of the partner's water. The final result is that the partner added 170 grams of water at 75.0°C.

What was the initial temperature of the water in your beaker?

• 90.0 degrees Celsius

• 58.0 degrees Celsius

• 75.0 degrees Celsius

• 69.0 degrees Celsius

What is the density of water assumed in this problem?

• 1.5 grams per mL

• 0.5 grams per mL

• 1 gram per mL

• 2 grams per mL

What is the heat capacity of water used in the calculations?

• 5.19 joules per gram Kelvin

• 4.19 joules per gram Kelvin

• 3.19 joules per gram Kelvin

• 6.19 joules per gram Kelvin

What was the initial temperature of your partner's water?

• 58.0 degrees Celsius

• 69.0 degrees Celsius

• 90.0 degrees Celsius

• 75.0 degrees Celsius

What is the temperature change (ΔT) for your water?

• 9 degrees Celsius

• 11 degrees Celsius

• 17 degrees Celsius

• 6 degrees Celsius

How much heat was transferred by your water?

• 6148 joules

• 5148 joules

• 4148 joules

• 3148 joules

What is the temperature change (ΔT) for your partner's water?

• 3 degrees Celsius

• 9 degrees Celsius

• 6 degrees Celsius

• 11 degrees Celsius

What was the calculated mass of water added by your partner before rounding?

• 170 grams

• 150 grams

• 165 grams

• 160 grams

What is the final rounded mass of water added by your partner?

• 170 grams

• 165 grams

• 160 grams

• 150 grams

What was the final temperature of the mixed water?

• 58.0 degrees Celsius

• 75.0 degrees Celsius

• 90.0 degrees Celsius

• 69.0 degrees Celsius