Gas Law Conversions and Calculations

Gas Law Conversions and Calculations

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to solve a gas law problem using the ideal gas law. It begins by identifying the given values: grams, temperature, and pressure, and the need to find volume. The tutorial demonstrates converting grams of carbon dioxide to moles, using the ideal gas law with the appropriate R constant, and ensuring all units are consistent. The final volume is calculated, considering significant digits, and the importance of unit consistency is emphasized.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal in this gas law problem?

To find the temperature

To find the number of moles

To find the pressure

To find the volume

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert grams to moles in this problem?

Multiply by the molar mass

Subtract the molar mass

Add the molar mass

Divide by the molar mass

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of carbon dioxide used in the conversion?

28.0 g/mol

44.1 g/mol

18.0 g/mol

32.0 g/mol

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What should you do if you need help converting from moles to grams?

Use a calculator

Ask a friend

Guess the conversion

Refer to the video description link

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which gas constant should be used when pressure is in atmospheres?

The one with units of Pa

The one with units of psi

The one with units of atm

The one with units of mmHg

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it necessary to convert temperature to Kelvin?

Because Celsius is not a valid unit

Because the ideal gas law requires temperature in Kelvin

Because Kelvin is easier to calculate

Because it simplifies the equation

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final calculated volume in liters?

0.60 L

0.594 L

0.531 L

0.59 L

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