Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between copper(II) sulfate and sodium bicarbonate. It begins by balancing the molecular equation, then discusses the states of the substances involved, highlighting the solubility rules and identifying the precipitate. The tutorial proceeds to form the complete ionic equation, identifying and removing spectator ions to derive the net ionic equation. The importance of charge balance is emphasized, and the tutorial concludes with a summary of the process.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a net ionic equation?

Balance the molecular equation

Write the complete ionic equation

Identify the spectator ions

Determine the precipitate

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is generally soluble?

Copper(II) carbonate

Sodium carbonate

Calcium carbonate

Lead(II) sulfate

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of copper(II) carbonate in the reaction?

Solid

Gas

Liquid

Aqueous

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What do you obtain by splitting strong electrolytes into ions?

Net ionic equation

Molecular equation

Complete ionic equation

Balanced equation

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are spectator ions?

Ions that do not change during the reaction

Ions that form the precipitate

Ions that are gases

Ions that participate in the reaction

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are removed to form the net ionic equation?

Precipitate ions

Product ions

Reactant ions

Spectator ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is copper(II) carbonate not split into ions in the net ionic equation?

It is a solid precipitate

It is an aqueous solution

It is a liquid

It is a gas

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