Net Ionic Equations and Reactions

Net Ionic Equations and Reactions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between strontium nitrate and potassium iodate. It begins with balancing the molecular equation, determining the states of substances, and splitting strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The tutorial concludes by ensuring charge balance and identifying the precipitate formed in the reaction.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation?

Determine solubility

Balance the molecular equation

Identify spectator ions

Write the complete ionic equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you balance the number of nitrate ions in the molecular equation?

Add a coefficient of 2

Add a coefficient of 1

Add a coefficient of 4

Add a coefficient of 3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is typically slightly soluble?

Strontium iodate

Potassium iodate

Potassium nitrate

Strontium nitrate

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What do you call ions that appear on both sides of the complete ionic equation?

Spectator ions

Balanced ions

Net ions

Neutral ions

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of removing spectator ions from the complete ionic equation?

To identify reactants

To simplify the net ionic equation

To balance the equation

To determine solubility

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net charge of the products in the net ionic equation?

Positive

Depends on the reactants

Negative

Zero

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to strontium iodate in the reaction?

It dissolves completely

It forms a precipitate

It remains unchanged

It reacts with potassium

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