

Oxidation States in Na2S4O6
Interactive Video
•
Chemistry
•
10th - 12th Grade
•
Practice Problem
•
Hard
Olivia Brooks
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the compound Na2S4O6 commonly known as?
Sodium sulfate
Sodium sulfide
Sodium tetrathionate
Sodium thiosulfate
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why do the oxidation numbers in a neutral compound add up to zero?
Because the compound has no net charge
Because the compound is acidic
Because the compound is covalent
Because the compound is ionic
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the oxidation state of sodium in Na2S4O6?
+1
+2
0
-1
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the typical oxidation state of oxygen in compounds?
-2
-1
0
+1
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the average oxidation state of sulfur in Na2S4O6 calculated?
By dividing the total oxidation state by the number of sulfur atoms
By subtracting the oxidation state of sodium from oxygen
By adding the oxidation states of sodium and oxygen
By multiplying the oxidation state of oxygen by the number of sulfur atoms
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the average oxidation state of sulfur in Na2S4O6?
3
2
3.5
2.5
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why might sulfur have a fractional oxidation state in Na2S4O6?
Because it is an average of different oxidation states
Because sulfur is bonded to sodium
Because sulfur is a non-metal
Because sulfur is bonded to oxygen
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