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Spectator Ions and Net Ionic Equations

Spectator Ions and Net Ionic Equations

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Practice Problem

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial explains how to balance the net ionic equation for the reaction between mercury 1 nitrate and sodium chloride. It begins by introducing the concept of net ionic equations and the unique nature of the mercury 1 ion. The tutorial then guides viewers through balancing the molecular equation, determining the states of the compounds using solubility rules, and forming the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The tutorial concludes by verifying the balanced net ionic equation, ensuring both charge and atom balance.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the mercury(I) ion in the net ionic equation?

2-

1-

2+

1+

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to balance the molecular equation first?

To ensure the equation is aesthetically pleasing

To make sure the number of atoms is equal on both sides

To simplify the equation

To avoid using coefficients

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which compound is insoluble and forms a precipitate in this reaction?

Sodium nitrate

Mercury(I) chloride

Sodium chloride

Mercury(I) nitrate

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of sodium nitrate in the reaction?

Aqueous

Liquid

Solid

Gas

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of splitting strong electrolytes into ions?

To balance the equation

To change the reaction

To identify spectator ions

To make the equation longer

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Mercury ions

All ions

Nitrate and sodium ions

Chloride ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net charge of the balanced net ionic equation?

1+

2+

2-

0

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