Net Ionic Equations and Reactions

Net Ionic Equations and Reactions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to write and balance a net ionic equation for the reaction between chromium-3 hydroxide and hydrochloric acid. It begins with balancing the molecular equation, assigning states to each substance, and splitting strong electrolytes into ions. Spectator ions are identified and crossed out, leading to the final balanced net ionic equation. The tutorial emphasizes the importance of charge conservation and atom balance in the process.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in balancing a net ionic equation?

Identify spectator ions

Split strong electrolytes into ions

Balance the molecular equation

Determine the states of substances

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many chlorine atoms are needed to balance the molecular equation for the reaction between chromium-3 hydroxide and hydrochloric acid?

Three

Two

One

Four

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is generally insoluble in water?

Ammonium hydroxide

Chlorides

Group 1 hydroxides

Chromium-3 hydroxide

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What state is hydrochloric acid in during the reaction?

Aqueous

Solid

Liquid

Gas

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which substances are not split into ions when writing net ionic equations?

Aqueous solutions

Strong acids

Weak bases

Solids, liquids, and gases

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are spectator ions?

Ions that change state during the reaction

Ions that are only present in the products

Ions that are the same on both sides of the equation

Ions that participate in the reaction

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net ionic equation for the reaction between chromium-3 hydroxide and hydrochloric acid?

Cr(OH)3 + 3HCl → CrCl3 + 3H2O

Cr3+ + 3OH- + 3H+ + 3Cl- → Cr3+ + 3Cl- + 3H2O

Cr(OH)3 + 3H+ → Cr3+ + 3H2O

3HCl → 3H+ + 3Cl-

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