Oxidation Numbers and Compounds

The video tutorial explains how to determine the oxidation numbers for each element in H2CrO4. It starts by applying general rules for oxidation states, identifying hydrogen as +1 and oxygen as -2. The tutorial then calculates the oxidation state of chromium by setting up an equation based on the compound's neutrality. The video also discusses how to identify bonding in H2CrO4, emphasizing the chromate ion and the role of hydrogen in balancing charges. The tutorial concludes with a summary of the oxidation numbers for each element in the compound.

What is the general rule for the oxidation number of hydrogen when bonded to nonmetals?

• +1

• 0

• -1

• +2

What is the typical oxidation number for oxygen in compounds?

• -1

• 0

• +2

• -2

How many hydrogen atoms are present in H2CrO4?

• 1

• 4

• 2

• 3

What is the oxidation number of chromium in H2CrO4?

• +3

• +5

• +6

• +4

In the compound H2CrO4, what is the total oxidation number for all oxygen atoms combined?

• -2

• -6

• -8

• -4

What is the charge of the chromate ion (CrO4) in H2CrO4?

• -1

• -2

• +1

• +2

Why are the hydrogens in H2CrO4 bonded to oxygen?

• Because H2CrO4 is a metal

• Because H2CrO4 is a salt

• Because H2CrO4 is an acid

• Because H2CrO4 is a base

What is the oxidation number of hydrogen in H2CrO4?

• +2

• 0

• +1

• -1

How does the oxidation number of chromium in H2CrO4 help in balancing the compound?

• It makes the compound ionic

• It makes the compound basic

• It makes the compound acidic

• It makes the compound neutral

What is the overall charge of the compound H2CrO4?

• 0

• -2

• -1

• +1