Electronegativity and Covalent Compounds

Electronegativity and Covalent Compounds

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explores whether BRF5 is an ionic or covalent compound. It begins by identifying bromine and fluorine on the periodic table, noting that both are non-metals, which suggests a covalent bond. The video then calculates the electronegativity difference between bromine and fluorine, finding it to be 1.02. This value, being less than 1.7, confirms that BRF5 is a covalent compound. The tutorial concludes with a summary of the findings.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of elements are bromine and fluorine, and what does this suggest about the type of compound BRF5 is?

Bromine is a non-metal and fluorine is a metal, suggesting an ionic compound.

Bromine is a metal and fluorine is a non-metal, suggesting a metallic compound.

Both are non-metals, suggesting a covalent compound.

Both are metals, suggesting an ionic compound.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of having two non-metals bonded together in BRF5?

It indicates a metallic bond.

It suggests a covalent bond.

It suggests an ionic bond.

It indicates a hydrogen bond.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the electronegativity difference between bromine and fluorine?

3.98

2.0

1.02

0.5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is BRF5 considered a covalent compound based on electronegativity?

The difference is less than 0.5, indicating a covalent bond.

The difference is less than 1.7, indicating a covalent bond.

The difference is greater than 2.0, indicating a covalent bond.

The difference is exactly 1.7, indicating a covalent bond.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is another name for a covalent compound?

Hydrogen compound

Metallic compound

Molecular compound

Ionic compound