Net Ionic Equations and Solubility

Net Ionic Equations and Solubility

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between ammonium carbonate and barium hydroxide. It begins with balancing the molecular equation and identifying the states of each substance, highlighting the solubility rules. The tutorial then demonstrates how to split strong electrolytes into ions to form the complete ionic equation, noting that solids, gases, and liquids remain intact. Since there are no spectator ions, the complete ionic equation is the same as the net ionic equation. The video concludes by ensuring charge and atom balance, with a brief discussion on ammonia's behavior as a weak electrolyte.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing the net ionic equation for ammonium carbonate and barium hydroxide?

Identify spectator ions

Balance the molecular equation

Determine the solubility of compounds

Write the complete ionic equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is ammonium carbonate considered soluble?

Because it forms a precipitate

Because ammonium compounds are generally soluble

Because all carbonates are soluble

Because it is a strong acid

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of barium carbonate in the reaction?

Liquid

Solid

Gas

Aqueous

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is ammonia treated in the net ionic equation?

As a strong electrolyte

As a weak electrolyte

As a solid

As a spectator ion

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of water in the reaction?

Gas

Liquid

Solid

Aqueous

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which substances are not split into ions in the complete ionic equation?

All reactants

All products

Strong acids

Solids, gases, and liquids

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are there no spectator ions in this reaction?

All ions are the same in reactants and products

The reaction does not involve ions

Spectator ions are not considered

All ions are different in reactants and products

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