Balancing Chemical Equations for Ethanol

The video tutorial explains how to balance the chemical equation for ethanol reacting with sodium metal. It begins by counting the atoms on both the reactant and product sides, highlighting the importance of careful counting. The instructor then discusses strategies for balancing, such as making hydrogen atoms an even number. Through step-by-step adjustments, the equation is balanced, with a focus on ensuring all atoms are accounted for. The tutorial concludes with a summary of the balanced equation.

What is the first step in balancing the equation for ethanol and sodium metal?

• Balance the sodium atoms first

• Count the atoms on the product side

• Add coefficients randomly

• Count the atoms on the reactant side

How many hydrogen atoms are present in the reactants initially?

• Five

• Six

• Seven

• Eight

What is the total number of hydrogen atoms on the product side before balancing?

• Eight

• Seven

• Six

• Five

What strategy is suggested to balance the hydrogen atoms?

• Add more sodium atoms

• Make hydrogen atoms an odd number

• Remove oxygen atoms

• Make hydrogen atoms an even number

What coefficient is placed in front of ethanol to help balance the equation?

• 1

• 2

• 4

• 3

After updating the coefficients, how many hydrogen atoms are there in total?

• 10

• 13

• 11

• 12

How many oxygen atoms are present on both sides after balancing?

• One

• Two

• Three

• Four

What is the final step to ensure the equation is balanced?

• Remove excess hydrogen

• Add more ethanol

• Check the sodium atoms

• Add more oxygen

What was the key trick to balancing this equation?

• Adding more reactants

• Making hydrogen an even number

• Removing products

• Balancing sodium first

What is the final balanced equation for ethanol and sodium metal?

• C2H5OH + 2Na → C2H5ONa + 2H2

• 2C2H5OH + 2Na → 2C2H5ONa + H2

• C2H5OH + Na → C2H5ONa + H2

• 2C2H5OH + Na → C2H5ONa + 2H2