Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains how to write and balance net ionic equations, using sodium sulfate and strontium chloride as examples. It covers balancing the molecular equation, determining the states of compounds, splitting strong electrolytes into ions, and identifying spectator ions. The tutorial concludes with the final balanced net ionic equation, ensuring both charge and atom balance.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation?

Balance the molecular equation

Identify spectator ions

Write the net ionic equation

Determine solubility

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you balance the number of sodium atoms in the molecular equation?

Add a coefficient of 2 in front of SrSO4

Add a coefficient of 2 in front of Na2SO4

Add a coefficient of 2 in front of NaCl

Add a coefficient of 2 in front of SrCl2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following compounds is generally soluble?

Lead sulfate

Sodium chloride

Barium sulfate

Strontium sulfate

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to strontium sulfate in the reaction?

It forms a precipitate

It remains as ions

It dissolves completely

It reacts with sodium

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of spectator ions in a net ionic equation?

They form a precipitate

They participate in the reaction

They are removed from the equation

They change the charge balance

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Strontium and sulfate ions

Sodium and chloride ions

Strontium and chloride ions

Sodium and sulfate ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net ionic equation for the reaction between sodium sulfate and strontium chloride?

Na2SO4 + SrCl2 → 2NaCl + SrSO4

2Na+ + SO4^2- + Sr^2+ + 2Cl- → SrSO4 + 2Na+ + 2Cl-

SO4^2- + Sr^2+ → SrSO4

Na2SO4 + SrCl2 → SrSO4 + 2NaCl

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