Balancing Chemical Equations Concepts

The video tutorial explains how to balance the chemical equation for diborane (B2H6) reacting with oxygen gas (O2). It begins by counting the atoms on both sides of the equation, focusing on boron, hydrogen, and oxygen. The tutorial then demonstrates balancing the boron and hydrogen atoms, followed by the oxygen atoms, ensuring the equation is balanced. The video concludes with a review of the balanced equation and the states of the reactants and products.

What is the initial count of boron atoms on the reactant side?

• Four

• Two

• One

• Three

How many hydrogen atoms are initially present on the reactant side?

• Seven

• Six

• Five

• Four

What is the first step in balancing the equation?

• Balancing oxygen atoms

• Balancing the entire equation at once

• Balancing hydrogen atoms

• Balancing boron atoms

After balancing boron, how many boron atoms are on the product side?

• Four

• Two

• One

• Three

What coefficient is placed in front of water to balance hydrogen atoms?

• Three

• Four

• Two

• One

How many total oxygen atoms are there after balancing?

• Six

• Five

• Four

• Seven

What is the final step in ensuring the equation is balanced?

• Recounting all atoms

• Adding more reactants

• Removing excess products

• Changing the equation

What is the state of matter for water in the balanced equation?

• Solid

• Plasma

• Liquid

• Gas

What is the state of matter for diborane in the balanced equation?

• Solid

• Plasma

• Liquid

• Gas

What is the state of matter for the product containing boron?

• Gas

• Liquid

• Plasma

• Solid