Moles and Grams Conversions

Moles and Grams Conversions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Practice Problem

Hard

Created by

Lucas Foster

FREE Resource

This video tutorial demonstrates how to convert 0.63 moles of aluminum carbonate (Al2(CO3)3) to grams. It explains the process of finding the molar mass by adding the atomic masses from the periodic table, which is 233.99 grams per mole for aluminum carbonate. The tutorial shows how to multiply the number of moles by the molar mass to get the mass in grams, resulting in 147.41 grams. It also covers the reverse process of converting grams to moles by dividing the mass by the molar mass.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial quantity of aluminum carbonate given in moles for the conversion problem?

0.50 moles

0.63 moles

1.00 mole

2.00 moles

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of aluminum carbonate used in the conversion?

150.50 grams per mole

233.99 grams per mole

200.00 grams per mole

300.00 grams per mole

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert moles to grams in this context?

Subtract molar mass from moles

Divide moles by molar mass

Multiply moles by molar mass

Add moles to molar mass

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of converting 0.63 moles of aluminum carbonate to grams?

50.00 grams

200.00 grams

100.00 grams

147.41 grams

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If you have grams and need to find moles, what should you do?

Divide grams by molar mass

Multiply grams by molar mass

Subtract molar mass from grams

Add grams to molar mass

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