Net Ionic Equations and Reactions

Net Ionic Equations and Reactions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between iron and silver nitrate. It begins by balancing the molecular equation, assigning states to each substance, and identifying the reaction as a single displacement. The tutorial then demonstrates how to split strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and crossed out to derive the net ionic equation, ensuring that both charge and atoms are balanced.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a net ionic equation?

Determine the states of substances

Identify spectator ions

Balance the molecular equation

Write the complete ionic equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you balance the number of nitrate ions in the equation?

Add a coefficient of 2 in front of Fe

Add a coefficient of 3 in front of AgNO3

Add a coefficient of 2 in front of Ag

Add a coefficient of 2 in front of AgNO3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What state is assigned to nitrates in the equation?

Gas

Aqueous

Solid

Liquid

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of reaction is Fe + AgNO3?

Synthesis

Double displacement

Decomposition

Single displacement

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of splitting strong electrolytes into ions?

To balance the equation

To identify spectator ions

To write the molecular equation

To determine the reaction type

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Hydrogen ions

Iron ions

Silver ions

Nitrate ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to spectator ions in the net ionic equation?

They are included in the equation

They are converted to solids

They are removed from the equation

They are doubled in the equation

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