Net Ionic Equations and Solubility

Net Ionic Equations and Solubility

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between silver nitrate and ammonium iodide. It begins with balancing the molecular equation, followed by determining the solubility and states of the compounds involved. The formation of a precipitate, silver iodide, is discussed, and the complete ionic equation is derived by splitting strong electrolytes into ions. Spectator ions are identified and removed to obtain the net ionic equation. The tutorial concludes by ensuring the charge balance and atom count are correct, resulting in a neutral compound.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation?

Write the complete ionic equation

Identify spectator ions

Balance the molecular equation

Determine the solubility of compounds

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is generally soluble according to solubility rules?

Silver compounds

Nitrates

Iodides

Chlorides

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of solubility rules in writing net ionic equations?

To identify spectator ions

To determine the charge of ions

To predict the formation of precipitates

To balance the molecular equation

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is silver iodide considered insoluble in this reaction?

It dissolves in water

It forms a precipitate

It is a strong electrolyte

It reacts with ammonium

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which compound forms a solid precipitate in this reaction?

Ammonium iodide

Silver nitrate

Silver iodide

Ammonium nitrate

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the silver ion in the complete ionic equation?

1-

2+

0

1+

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Silver and iodide ions

Ammonium and nitrate ions

Silver and nitrate ions

Ammonium and iodide ions

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