Molecular Geometry and AXE Notation

Molecular Geometry and AXE Notation

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Practice Problem

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to draw the Lewis structure for the iodine dibromide cation (IBr2+). It begins by counting the valence electrons, placing iodine at the center, and arranging bromine atoms on either side. The video details the process of completing octets and calculating formal charges, ensuring the structure is correct. It also covers the molecular geometry, identifying it as bent, and the electron geometry as tetrahedral. The tutorial concludes with the use of AXE notation to confirm the molecular geometry.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons in the IBr2+ ion?

18

20

24

22

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is iodine placed at the center of the IBr2+ Lewis structure?

It is the least electronegative element.

It has the highest atomic number.

It has the smallest atomic radius.

It is the most electronegative element.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to complete the octets of the bromine atoms in IBr2+?

12

20

16

8

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on the central iodine atom in the IBr2+ ion?

0

+1

-1

+2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molecular geometry of the IBr2+ ion?

Tetrahedral

Bent

Linear

Trigonal planar

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate bond angle in the bent molecular geometry of IBr2+?

120 degrees

109.5 degrees

90 degrees

180 degrees

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the electron geometry of the IBr2+ ion?

Linear

Octahedral

Trigonal planar

Tetrahedral

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