Net Ionic Equations and Solubility

The video tutorial explains how to write a balanced net ionic equation for the reaction between iron(II) sulfate and ammonium sulfide. It begins with balancing the molecular equation, then discusses the solubility and states of the reactants and products. The tutorial proceeds to break down the substances into ions for the complete ionic equation and identifies spectator ions to form the net ionic equation. Finally, it concludes with a discussion on charge conservation and the formation of a precipitate.

What is the first step in writing a net ionic equation?

• Write the complete ionic equation

• Balance the molecular equation

• Identify spectator ions

• Determine the solubility of compounds

Which of the following is generally soluble?

• Sulfides

• Ammonium compounds

• Iron(II) sulfide

• Carbonates

What state symbol is used for a substance that dissolves in water?

• (l)

• (s)

• (g)

• (aq)

What is the charge on the sulfate ion?

• 1-

• 2+

• 2-

• 1+

How many ammonium ions are present in the reactants of the complete ionic equation?

• Four

• One

• Three

• Two

What do we call ions that appear on both sides of the complete ionic equation?

• Spectator ions

• Reactant ions

• Net ions

• Precipitate ions

Which ion is a spectator ion in the reaction between iron(II) sulfate and ammonium sulfide?

• Iron(II) ion

• Sulfate ion

• Sulfide ion

• Ammonium ion

What is the net charge of the reactants in the net ionic equation?

• 1+

• 0

• 2-

• 2+

What is the physical state of the precipitate formed in the reaction?

• Aqueous

• Solid

• Liquid

• Gas

What ensures that the net ionic equation is correctly balanced?

• Equal number of atoms on both sides

• Equal number of ions on both sides

• Equal number of electrons on both sides

• Equal number of molecules on both sides