Tin and Cyanide Compounds

The video tutorial explains how to write the chemical formula for tin(IV) cyanide. It begins by identifying the element symbol for tin (Sn) and its charge as a transition metal. The tutorial then describes the cyanide ion (CN) and its charge. It emphasizes the importance of balancing ionic charges to achieve a net charge of zero. The video concludes by demonstrating the final formula for tin(IV) cyanide as Sn(CN)4, ensuring the charges are balanced.

What is the element symbol for tin as found on the periodic table?

• Ti

• Sn

• Pb

• Te

What is the charge of tin in the compound tin(IV) cyanide?

• 3+

• 1+

• 2+

• 4+

What elements make up the cyanide ion?

• Oxygen and Hydrogen

• Carbon and Oxygen

• Nitrogen and Hydrogen

• Carbon and Nitrogen

What is the ionic charge of the cyanide ion?

• 2-

• 2+

• 1-

• 1+

Why do the charges in an ionic compound need to balance?

• To increase the compound's reactivity

• To decrease the compound's solubility

• To make the compound more stable

• To ensure the compound is neutral

How many cyanide ions are needed to balance the charge of one tin ion in tin(IV) cyanide?

• Four

• Five

• Three

• Two

What is the purpose of using parentheses in the formula for tin(IV) cyanide?

• To indicate the charge of the compound

• To show the number of tin atoms

• To denote multiple cyanide ions

• To highlight the transition metal

What is the correct chemical formula for tin(IV) cyanide?

• Sn(CN)2

• Sn(CN)4

• Sn(CN)3

• Sn(CN)5