Tin(IV) Bromide and Ionic Compounds

This video tutorial explains how to write the chemical formula for Tin(IV) Bromide. It begins by identifying the element symbols for tin (Sn) and bromine (Br) from the periodic table. The video then discusses the charges of these elements, with tin having a +4 charge and bromine a -1 charge. To balance the charges and achieve a net charge of zero, four bromine atoms are needed for each tin atom, resulting in the formula SnBr4. The tutorial concludes with a summary of the process.

What is the element symbol for tin as mentioned in the video?

• Sb

• Ti

• Sn

• Pb

What charge does bromine typically have according to the periodic table?

• +2

• +1

• -2

• -1

Why is tin(IV) bromide considered an ionic compound?

• It contains only non-metals.

• It contains a metal and a non-metal.

• It contains only metals.

• It contains noble gases.

How many bromine atoms are needed to balance the charge of tin in tin(IV) bromide?

• 3

• 5

• 2

• 4

What is the final formula for tin(IV) bromide as derived in the video?

• SnBr3

• SnBr

• SnBr2

• SnBr4