Net Ionic Equations and Solubility

This video tutorial guides viewers through writing a balanced net ionic equation for the reaction between silver nitrate and lithium sulfate. It begins with balancing the molecular equation, followed by identifying the solubility and states of the substances involved. The tutorial then explains how to form the complete ionic equation by splitting strong electrolytes into ions. Finally, it demonstrates deriving the net ionic equation by removing spectator ions, ensuring charge conservation and balanced atoms.

What is the main goal of the video tutorial?

• To discuss the periodic table.

• To demonstrate the properties of silver nitrate.

• To write the balanced net ionic equation for a given reaction.

• To explain the concept of solubility rules.

What is the first step in balancing the molecular equation?

• Identifying the spectator ions.

• Adjusting the coefficients to balance the number of atoms.

• Writing the net ionic equation.

• Determining the solubility of the compounds.

Which compound is identified as insoluble in the reaction?

• Lithium nitrate

• Silver sulfate

• Silver nitrate

• Lithium sulfate

What happens to soluble compounds in the complete ionic equation?

• They remain as whole compounds.

• They are split into their respective ions.

• They form a precipitate.

• They are ignored.

How many silver ions are present in the complete ionic equation?

• Three

• Two

• Four

• One

What is the charge of the sulfate ion in the reaction?

• 2-

• 2+

• 1+

• 1-

What is the purpose of removing spectator ions in the net ionic equation?

• To determine the solubility.

• To identify the precipitate.

• To balance the charges.

• To simplify the equation by focusing on the actual chemical change.

Why is silver sulfate not split in the net ionic equation?

• It is a precipitate and remains as a solid.

• It is a spectator ion.

• It is not involved in the reaction.

• It is a soluble compound.

What is conserved in the net ionic equation?

• Neither charge nor number of atoms

• Both charge and number of atoms

• Only the charge

• Only the number of atoms

What is the net charge of the final compound in the net ionic equation?

• 0

• 1+

• 1-

• 2+