Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between silver nitrate and potassium iodate. It begins with balancing the molecular equation and identifying the states of each compound using solubility rules. The tutorial then demonstrates how to split strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The video concludes with a check for charge and atom balance, ensuring the equation is correct.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a net ionic equation?

Write the states of each substance

Balance the molecular equation

Identify spectator ions

Split strong electrolytes into ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to solubility rules, which of the following is generally soluble?

Lead sulfate

Silver iodate

Potassium iodate

Calcium carbonate

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to potassium iodate in the reaction?

It reacts with silver nitrate to form a gas

It forms a precipitate

It remains as a solid

It dissolves and dissociates into ions

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the silver ion in the complete ionic equation?

1+

2-

2+

1-

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Potassium and iodate ions

Silver and iodate ions

Potassium and nitrate ions

Silver and nitrate ions

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net ionic equation for the reaction between silver nitrate and potassium iodate?

Ag+ + NO3- → AgNO3

Ag+ + IO3- → AgIO3

K+ + NO3- → KNO3

Ag+ + K+ → AgK

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why don't we split solids in net ionic equations?

They are not involved in the reaction

They do not dissociate into ions

They are spectator ions

They are always soluble

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