Balancing Combustion Reactions

This video tutorial demonstrates how to balance the chemical equation for the combustion of C6H14 with O2, resulting in carbon dioxide and water. The process involves counting and balancing carbon, hydrogen, and oxygen atoms, with a focus on strategies to handle even numbers and ensure the equation is balanced. The tutorial provides a step-by-step approach to achieve a balanced equation, highlighting the challenges and solutions encountered during the process.

What type of reaction is C6H14 + O2?

• Single replacement reaction

• Combustion reaction

• Decomposition reaction

• Synthesis reaction

How many carbon atoms are present in C6H14?

• 4

• 6

• 8

• 10

What is the first step in balancing the equation?

• Balance the hydrogen atoms

• Balance the entire equation at once

• Balance the oxygen atoms

• Balance the carbon atoms

How many hydrogen atoms are there in the product side initially?

• 2

• 4

• 6

• 14

What is the total number of oxygen atoms needed after balancing hydrogen?

• 14

• 21

• 19

• 12

Why is it challenging to balance the oxygen atoms?

• Because they are not present in the reactants

• Because they are not present in the products

• Because they are in odd numbers

• Because they are in even numbers

What strategy is used to handle the even number of oxygen atoms?

• Use a catalyst

• Add more reactants

• Remove some products

• Double the entire equation

What is the final number of oxygen molecules needed to balance the equation?

• 19

• 21

• 23

• 17

What is the final balanced equation for C6H14 + O2?

• C6H14 + 19O2 → 6CO2 + 7H2O

• 2C6H14 + 17O2 → 12CO2 + 14H2O

• 2C6H14 + 19O2 → 12CO2 + 14H2O

• C6H14 + 17O2 → 6CO2 + 7H2O

Who is the narrator of the video?

• Dr. C

• Dr. B

• Dr. D

• Dr. A