Net Ionic Equations and Solubility

Net Ionic Equations and Solubility

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial guides viewers through writing a balanced net ionic equation for the reaction between cadmium chloride and ammonium sulfide. It begins with balancing the molecular equation, followed by identifying the solubility and states of the substances involved. The tutorial then explains how to split strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The video concludes with a summary of the balanced net ionic equation, ensuring charge and atom balance.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation?

Determine the states of substances

Write the complete ionic equation

Balance the molecular equation

Identify spectator ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you balance the molecular equation for the reaction between cadmium chloride and ammonium sulfide?

Change the products

Remove spectator ions

Add more reactants

Adjust the coefficients

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of chlorides according to solubility rules?

Very soluble

Solid

Gas

Insoluble

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of reaction occurs when an insoluble compound forms and falls to the bottom of the test tube?

Synthesis reaction

Decomposition reaction

Precipitation reaction

Combustion reaction

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the cadmium ion in the complete ionic equation?

1+

1-

2-

2+

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are not split apart in the net ionic equation?

Solid ions

Spectator ions

Gas ions

Aqueous ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of identifying spectator ions in the complete ionic equation?

To increase reactants

To change the products

To simplify the equation

To balance the equation

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