Lewis Structures and Valence Electrons

This video tutorial explains how to write the Lewis structure for tin(II) bromide (SnBr2). It begins by counting the valence electrons of tin and bromine, then proceeds to construct the Lewis structure by placing tin in the center and bromine atoms on either side. The video discusses the exception to the octet rule for tin and checks the formal charges to ensure they are zero. Finally, it explores the molecular geometry of SnBr2, identifying it as bent due to the presence of a lone pair, and uses AXN notation to confirm this geometry.

What is the first step in writing the Lewis structure for SnBr2?

• Count the valence electrons

• Identify the molecular geometry

• Determine the formal charges

• Calculate the bond angles

How many valence electrons does tin contribute in SnBr2?

• 8

• 6

• 4

• 2

What is the total number of valence electrons in SnBr2?

• 22

• 18

• 16

• 20

Where is tin placed in the Lewis structure of SnBr2?

• In the center

• At the bottom

• On the side

• At the top

Why is tin in SnBr2 an exception to the octet rule?

• It is a noble gas

• It has fewer than eight electrons

• It has more than eight electrons

• It forms ionic bonds

What type of bond is formed between tin and bromine in SnBr2?

• Ionic bond

• Metallic bond

• Hydrogen bond

• Covalent bond

What is the formal charge on each element in SnBr2?

• +1

• -1

• 0

• +2

How many steric groups are present in SnBr2?

• 5

• 4

• 3

• 2

What is the molecular geometry of SnBr2?

• Linear

• Trigonal planar

• Bent

• Tetrahedral

What does the 'X' represent in the AXN notation for SnBr2?

• Lone pairs

• Central atom

• Bonded atoms

• Total electrons