Oxidation States and Chemical Compounds

Oxidation States and Chemical Compounds

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explains how to determine the oxidation numbers for each element in the compound P2H4. It starts by identifying the compound as neutral, meaning the sum of oxidation numbers is zero. The oxidation state of hydrogen is determined to be +1 when bonded to a non-metal like phosphorus. An equation is set up to solve for phosphorus's oxidation number, which is found to be -2. The tutorial concludes with a verification of the calculations, ensuring the sum of oxidation numbers equals zero.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the overall charge of the compound P2H4?

Positive

Negative

Neutral

Depends on the environment

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When hydrogen is bonded to a non-metal like phosphorus, what is its oxidation state?

+1

+2

-1

0

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many hydrogen atoms are present in P2H4?

5

4

2

3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation is set up to find the oxidation number of phosphorus in P2H4?

x + 4 = 0

x - 4 = 0

2x + 4 = 0

2x - 4 = 0

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the oxidation number of phosphorus in P2H4?

+2

-2

0

+1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why does the equation 2x + 4 = 0 make sense for P2H4?

Because 2 and 4 add up to zero

Because 4 and -4 add up to zero

Because 4 and 2 add up to zero

Because 2 and -2 add up to zero