Net Ionic Equations and Spectator Ions

The video tutorial explains the process of determining the net ionic equation for a reaction between sodium chloride and copper(II) sulfate. It begins by balancing the molecular equation and assigning states to each substance, noting that all are aqueous. This leads to the identification of spectator ions, which are present on both sides of the equation and thus cancel out, resulting in no net ionic equation. The tutorial concludes by emphasizing that no reaction occurs as the ions remain unchanged.

What is the first step in solving a net ionic equation?

• Determine the solubility of compounds

• Write the net ionic equation

• Balance the molecular equation

• Identify spectator ions

Why do we put a coefficient of 2 in front of NaCl in the balanced equation?

• To balance the number of chlorine atoms

• To balance the number of copper atoms

• To balance the number of sodium atoms

• To balance the number of sulfate ions

What is the state of sodium chloride in the reaction?

• Aqueous

• Gas

• Liquid

• Solid

Which of the following compounds is generally very soluble?

• Silver chloride

• Calcium carbonate

• Lead(II) sulfate

• Copper(II) sulfate

What happens to the ions in the solution during the reaction?

• They evaporate

• They react to form a new compound

• They remain unchanged

• They form a precipitate

What are spectator ions?

• Ions that participate in the reaction

• Ions that change state during the reaction

• Ions that do not change during the reaction

• Ions that form a new compound

Why is there no net ionic equation for this reaction?

• All ions are spectator ions

• All ions form a gas

• All ions form a solid

• All ions evaporate

What is the final observation about the ions in the beaker?

• They form a new compound

• They remain as they started

• They change color

• They precipitate out