Understanding Pb(CO3)2 and Carbonate Ions

The video tutorial explains how to determine the number of atoms in lead(IV) carbonate (PbCO3) by breaking down its chemical formula. It covers the calculation of individual atoms of lead, carbon, and oxygen, and explains how to use Avogadro's number to find the number of atoms in a mole. Additionally, it discusses the presence of carbonate ions in the compound.

What elements are present in the compound Pb(CO3)2?

• Lead, Carbon, and Oxygen

• Lead, Carbon, and Nitrogen

• Carbon, Oxygen, and Hydrogen

• Lead, Oxygen, and Hydrogen

How many oxygen atoms are present in one formula unit of Pb(CO3)2?

• Two

• Three

• Six

• Nine

What is the total number of atoms in one formula unit of Pb(CO3)2?

• Fifteen

• Six

• Twelve

• Nine

What is the significance of the subscript '2' in Pb(CO3)2?

• It applies only to carbon atoms.

• It applies to the entire carbonate group.

• It indicates two oxygen atoms.

• It indicates two lead atoms.

How do you calculate the number of lead atoms in one mole of Pb(CO3)2?

• Multiply by Avogadro's number

• Multiply by 3

• Multiply by 6

• Multiply by 2

How many carbon atoms are there in one mole of Pb(CO3)2?

• 3 x Avogadro's number

• 6.02 x 10^23

• 1.20 x 10^24

• 2 x Avogadro's number

If you have one mole of Pb(CO3)2, how many moles of carbonate ions do you have?

• One

• Four

• Two

• Three

What is the charge of the carbonate ion in Pb(CO3)2?

• +2

• -1

• 0

• -2