Oxidation Numbers in NH4F

The video tutorial explains how to find the oxidation numbers for each element in ammonium fluoride (NH4F). It begins by introducing the concept of oxidation numbers and the neutrality of the compound. The tutorial then sets up an equation to calculate the oxidation numbers, explaining that hydrogen is +1, fluorine is -1, and nitrogen's oxidation number is determined by the equation. The calculation shows that nitrogen has an oxidation number of -3, ensuring the compound is neutral. The video concludes with a summary of the findings.

What is the compound NH4F commonly known as?

• Ammonium bromide

• Ammonium fluoride

• Ammonium chloride

• Ammonium iodide

Why do the oxidation numbers in NH4F add up to zero?

• Because it is an ionic compound

• Because it is a neutral compound

• Because it is a negatively charged compound

• Because it is a positively charged compound

What is the oxidation number of hydrogen when bonded to a non-metal?

• 0

• +2

• -1

• +1

What is the oxidation number of fluorine in NH4F?

• +2

• 0

• +1

• -1

How is the oxidation number of nitrogen in NH4F determined?

• By assuming it is always -3

• By using the known oxidation numbers of oxygen and hydrogen

• By assuming it is always +3

• By using the known oxidation numbers of hydrogen and fluorine

What is the oxidation number of nitrogen in NH4F?

• -3

• 0

• +3

• +5

What is the overall charge of the compound NH4F?

• Variable

• Positive

• Negative

• Neutral