Oxidation States and Ion Charges

This video tutorial explains how to determine the oxidation numbers for each element in the aluminate ion, AlOH4-. It begins by introducing the concept of oxidation numbers and their significance in ions. The video then discusses the typical oxidation states of aluminum, oxygen, and hydrogen, and sets up an equation to find the oxidation number of aluminum in the ion. The equation is solved step-by-step, demonstrating that the oxidation state of aluminum in AlOH4- is +3. The tutorial concludes with a summary of the findings.

What is the charge of the aluminate ion?

• -2

• +1

• -1

• 0

What is the usual oxidation state of aluminum?

• +2

• +1

• 0

• +3

What is the oxidation state of oxygen in most compounds?

• +1

• 0

• -2

• -1

When hydrogen is bonded to nonmetals, what is its typical oxidation state?

• -1

• +2

• 0

• +1

What equation is set up to find the oxidation state of aluminum in the aluminate ion?

• x + 4 = 0

• x - 4 = 0

• x - 4 = -1

• x + 4 = -1

What is the oxidation state of aluminum in the aluminate ion?

• +1

• +2

• +3

• 0

What should the sum of oxidation numbers equal in an ion?

• The number of atoms

• The charge of the ion

• The atomic number

• Zero