Ionic Equations and Solubility Concepts

Ionic Equations and Solubility Concepts

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to write and balance the net ionic equation for the reaction between sodium carbonate (Na2CO3) and chromium(II) bromide (CrBr2). It begins with balancing the molecular equation, then discusses the solubility and states of the substances involved. The tutorial proceeds to form the complete ionic equation by splitting strong electrolytes into their ions. Finally, it identifies spectator ions to derive the net ionic equation, ensuring charge and atom balance.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced molecular equation for a reaction?

Identify the spectator ions.

Determine the solubility of the compounds.

Balance the number of atoms for each element.

Write the net ionic equation.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following compounds is generally soluble in water?

Sodium carbonate

Chromium carbonate

Calcium phosphate

Lead sulfate

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to chromium carbonate in the reaction?

It dissolves in water

It forms a gas

It precipitates as a solid

It remains unchanged

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of a solubility table in writing ionic equations?

To check the solubility of compounds

To identify spectator ions

To determine the charges of ions

To balance the equation

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the carbonate ion?

2-

2+

1-

1+

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the complete ionic equation, which ions are not split apart?

Solid precipitates

Aqueous ions

Gaseous products

Liquid water

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are spectator ions?

Ions that are insoluble

Ions that participate in the reaction

Ions that do not change during the reaction

Ions that form the precipitate

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