Oxidation Numbers and Compounds

This video tutorial explains how to find the oxidation number of carbon in the compound Na2C2O4. It begins by noting that the compound is neutral, meaning the sum of oxidation numbers is zero. The video then details the oxidation numbers of sodium, carbon, and oxygen, and sets up an equation to solve for carbon's oxidation number. The solution shows that carbon has an oxidation number of +3. The tutorial concludes by summarizing the process and confirming the oxidation numbers for all elements in the compound.

What is the overall charge of the compound Na2C2O4?

• Neutral

• Negative

• Variable

• Positive

Which group on the periodic table does sodium belong to?

• Group 17

• Group 2

• Group 1

• Group 16

What is the typical oxidation number for oxygen in compounds?

• +2

• +1

• -2

• -1

In the compound Na2C2O4, what variable is used to represent the oxidation number of carbon?

• c

• y

• z

• x

What is the equation set up to find the oxidation number of carbon in Na2C2O4?

• 2x + 4 = 0

• x - 4 = 0

• 2x - 6 = 0

• x + 6 = 0

What is the oxidation number of carbon in Na2C2O4 after solving the equation?

• -2

• -3

• +3

• +2

How many carbons are present in the compound Na2C2O4?

• 4

• 3

• 2

• 1

What is the sum of all oxidation numbers in a neutral compound?

• 1

• 2

• 0

• -1