Neutralization and Double Replacement Reactions

Neutralization and Double Replacement Reactions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains the reaction between lead(II) hydroxide (Pb(OH)2) and hydrochloric acid (HCl), identifying it as both a neutralization and a double replacement reaction. The instructor describes how the base (Pb(OH)2) and the acid (HCl) react to form a salt (lead chloride) and water, highlighting the neutralization process. Additionally, the video covers the double replacement aspect, where positive ions switch places, and provides a step-by-step guide to balancing the chemical equation. The tutorial concludes with a recap of the key concepts discussed.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of compound is lead(II) hydroxide in the reaction?

An acid

A base

A salt

A metal

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of hydrochloric acid in the reaction?

It acts as a solvent

It acts as a base

It acts as a catalyst

It acts as an acid

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is formed when an acid and a base react in a neutralization reaction?

Only water

Only salt

Gas and water

Salt and water

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the pH level of the solution after a neutralization reaction?

Around 7

Around 10

Around 1

Around 14

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a double replacement reaction, what happens to the positive ions?

They remain unchanged

They form a gas

They switch places

They are removed

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the product formed when lead(II) hydroxide reacts with hydrochloric acid in a double replacement reaction?

Lead(II) nitrate

Lead(II) sulfate

Lead(II) carbonate

Lead(II) chloride

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the balanced chemical equation for the reaction between lead(II) hydroxide and hydrochloric acid?

Pb(OH)2 + 2HCl → PbCl2 + 2H2O

Pb(OH)2 + HCl → PbCl2 + 2H2O

Pb(OH)2 + HCl → PbCl2 + H2O

Pb(OH)2 + 2HCl → PbCl2 + H2

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