Net Ionic Equations and Precipitation

The video tutorial explains how to write a balanced net ionic equation for the reaction between barium nitrate and aluminum sulfate. It begins with balancing the molecular equation, followed by assigning states to each substance using solubility rules. The tutorial then demonstrates how to split strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The video concludes by ensuring charge and atom balance in the final equation.

What is the first step in writing a net ionic equation?

• Identify spectator ions

• Balance the molecular equation

• Assign states to each substance

• Write the complete ionic equation

How do you balance the number of nitrate ions in the equation?

• Add more aluminum ions

• Increase the number of sulfate ions

• Change the coefficient of barium nitrate

• Adjust the coefficient of aluminum nitrate

Which of the following is insoluble and forms a precipitate?

• Aluminum sulfate

• Barium nitrate

• Aluminum nitrate

• Barium sulfate

What is the charge of the aluminum ion in the complete ionic equation?

• 2+

• 3+

• 4+

• 1+

Which ions are considered spectator ions in this reaction?

• Barium ions

• Aluminum ions

• Sulfate ions

• Nitrate ions

Why do we not split solids in the complete ionic equation?

• They are not reactive

• They do not dissolve

• They are spectator ions

• They have no charge

What is the net charge of the products in the net ionic equation?

• 3+

• 1+

• 2+

• 0

What is the purpose of removing spectator ions?

• To simplify the equation

• To identify the precipitate

• To balance the charges

• To adjust the coefficients

What is the coefficient of barium sulfate in the net ionic equation?

• 4

• 3

• 2

• 1

How do you ensure the charges are balanced in the net ionic equation?

• Add more ions

• Check the periodic table

• Adjust the coefficients

• Remove spectator ions