Ionic Compounds and Reactions

The video tutorial explains how to write a balanced net ionic equation for the reaction between calcium chloride and cesium phosphate. It begins by balancing the molecular equation, then determines the states of the substances using solubility rules. The tutorial proceeds to write the complete ionic equation, identifying spectator ions, and finally presents the net ionic equation. The video concludes with a discussion on variations if cesium phosphate is treated as a solid.

What is the main objective of the video tutorial?

• To learn about the periodic table

• To write a balanced net ionic equation

• To explore the history of chemistry

• To understand chemical bonding

How many calcium atoms are needed to balance the molecular equation?

• Four

• Three

• Two

• One

What is the state of calcium chloride in the reaction?

• Aqueous

• Solid

• Liquid

• Gas

Which group on the periodic table is cesium found in?

• Group 3

• Group 2

• Group 4

• Group 1

What is the charge of the chloride ion?

• 2-

• 2+

• 1-

• 1+

How many cesium ions are present in the complete ionic equation?

• Two

• Four

• Six

• Eight

What happens to spectator ions in the net ionic equation?

• They form a new compound

• They are included in the final equation

• They are removed from the equation

• They change their charge

What is the charge of the phosphate ion?

• 1-

• 2-

• 3-

• 4-

What is the state of calcium phosphate in the reaction?

• Liquid

• Gas

• Solid

• Aqueous

What is the overall charge of the net ionic equation?

• Undefined

• Zero

• Negative

• Positive