Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between ammonium sulfide and cobalt(II) chloride. It begins with balancing the molecular equation, then discusses the solubility and states of the compounds involved. The tutorial proceeds to form the complete ionic equation by splitting strong electrolytes into ions. Spectator ions are identified and removed to derive the net ionic equation. The video concludes by ensuring charge conservation and atom balance in the final equation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation?

Balance the molecular equation

Write the complete ionic equation

Identify spectator ions

Determine the solubility of compounds

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you balance the molecular equation for ammonium sulfide and cobalt(II) chloride?

Add a coefficient of 3 to cobalt(II) chloride

Add a coefficient of 2 to ammonium chloride

Add a coefficient of 2 to cobalt(II) sulfide

Add a coefficient of 3 to ammonium sulfide

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following compounds is generally insoluble?

Ammonium sulfide

Cobalt(II) sulfide

Cobalt(II) chloride

Ammonium chloride

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of ammonium chloride in the reaction?

Solid

Liquid

Aqueous

Gas

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the cobalt ion in cobalt(II) chloride?

0

3+

2+

1+

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of writing the complete ionic equation?

To split strong electrolytes into ions

To determine solubility

To balance the charges

To identify the precipitate

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Sulfide and cobalt ions

Ammonium and chloride ions

Cobalt and chloride ions

Ammonium and sulfide ions

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