Net Ionic Equations and Spectator Ions

This video tutorial explains how to write the balanced net ionic equation for the reaction between sodium sulfite and concentrated nitric acid. It covers balancing the molecular equation, assigning states to each substance, forming the complete ionic equation, and deriving the net ionic equation by removing spectator ions. The tutorial emphasizes the importance of charge and atom balance in the final equation.

What is the main difference between using concentrated and dilute nitric acid in the reaction with sodium sulfite?

• Concentrated nitric acid produces different products.

• Dilute nitric acid is more reactive.

• Dilute nitric acid forms a precipitate.

• Concentrated nitric acid is less soluble.

What is the first step in balancing the molecular equation for the reaction?

• Balancing the oxygen atoms.

• Balancing the hydrogen atoms.

• Balancing the sodium atoms.

• Balancing the nitrogen atoms.

Which state is assigned to sodium compounds in the reaction?

• Aqueous

• Gas

• Liquid

• Solid

What is the charge of the sulfite ion in the complete ionic equation?

• 2-

• 1+

• 2+

• 3-

Which ions are considered spectator ions in this reaction?

• Sulfate ions

• Hydrogen ions

• Sodium ions

• Nitrate ions

What is the purpose of removing spectator ions in the net ionic equation?

• To simplify the equation.

• To balance the equation.

• To increase the reaction rate.

• To change the reaction products.

How is charge conservation verified in the net ionic equation?

• By ensuring the total charge is zero.

• By balancing the number of atoms.

• By checking that charges are equal on both sides.

• By counting the number of ions.

What is the final charge on both sides of the net ionic equation?

• -1

• 0

• +1

• -2

Why might the positive ion be placed first in the net ionic equation?

• It is a standard convention.

• It affects the reaction rate.

• It changes the reaction products.

• It balances the equation.

What is the significance of using concentrated nitric acid in this reaction?

• It increases the solubility of sodium sulfite.

• It prevents the formation of a precipitate.

• It ensures the formation of a gas.

• It produces different products than dilute acid.