Balancing Chemical Reactions and Equations

The video tutorial explains how to balance the chemical equation for the reaction between lead(II) oxide (PbO) and hydrochloric acid (HCl). It begins by identifying the states of the reactants and products, then proceeds to balance the equation by adjusting the coefficients to ensure the number of atoms for each element is equal on both sides. The tutorial concludes with the final balanced equation and a brief closing statement.

What is the state of matter for hydrochloric acid in the reaction with lead(II) oxide?

• Solid

• Liquid

• Aqueous

• Gas

How many lead atoms are present on the reactant side of the initial equation?

• Four

• Three

• One

• Two

In the initial unbalanced equation, how many hydrogen atoms are present on the product side?

• Four

• Three

• Two

• One

What is the first step to balance the hydrogen atoms in the equation?

• Add a coefficient of 2 in front of HCl

• Add a coefficient of 3 in front of PbO

• Add a coefficient of 2 in front of PbO

• Add a coefficient of 3 in front of HCl

After balancing, how many chlorine atoms are there on the reactant side?

• Two

• One

• Four

• Three

What is the final balanced equation for the reaction between PbO and HCl?

• PbO + HCl → PbCl + H2O

• 2PbO + HCl → PbCl2 + H2O

• PbO + 2HCl → PbCl2 + H2O

• PbO + HCl → PbCl2 + H2O