Net Ionic Equations and Solubility

Net Ionic Equations and Solubility

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Practice Problem

Hard

Created by

Aiden Montgomery

FREE Resource

This video tutorial explains how to write balanced net ionic equations for the reaction between barium hydroxide and iron(II) sulfate. It covers balancing molecular equations, determining solubility and states of compounds, and identifying precipitation reactions. The tutorial also details forming complete and net ionic equations, highlighting the importance of charge and atom balancing. The video concludes with a demonstration of the balanced net ionic equation, ensuring both charge and atom balance.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation?

Identify spectator ions

Write the complete ionic equation

Determine the solubility of compounds

Balance the molecular equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is generally soluble according to solubility rules?

Barium sulfate

Iron(II) hydroxide

Sodium chloride

Lead sulfate

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of reaction occurs when a solid forms and settles at the bottom of a test tube?

Combustion reaction

Precipitation reaction

Decomposition reaction

Synthesis reaction

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following compounds is insoluble and forms a solid in the reaction?

Sodium sulfate

Iron(II) sulfate

Barium hydroxide

Barium sulfate

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the barium ion in the complete ionic equation?

1-

2+

1+

2-

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why don't we split solids into ions in the net ionic equation?

Solids are not reactive

Solids do not dissolve in water

Solids have no charge

Solids are spectator ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of identifying spectator ions in a reaction?

To balance the equation

To simplify the net ionic equation

To determine solubility

To identify reactants

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