Net Ionic Equations and Solubility

This video tutorial explains how to write a balanced net ionic equation for the reaction between lead(II) nitrate and copper(II) sulfate. It begins with balancing the molecular equation and determining the states of each substance using solubility rules. The tutorial then demonstrates how to split strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The video concludes by ensuring charge conservation and balanced atoms in the final equation.

What is the first step in writing a balanced net ionic equation?

• Determine the solubility of compounds

• Write the complete ionic equation

• Identify spectator ions

• Balance the molecular equation

Which of the following is generally soluble in water?

• Barium sulfate

• Silver chloride

• Copper(II) sulfate

• Lead sulfate

Which compound forms a precipitate in the reaction?

• Copper(II) sulfate

• Lead sulfate

• Lead(II) nitrate

• Copper(II) nitrate

What is the charge on the nitrate ion?

• 1+

• 2-

• 1-

• 2+

What is the charge on the copper ion in this reaction?

• 1+

• 2+

• 2-

• 1-

Which ion is not split in the complete ionic equation?

• Sulfate ion

• Lead(II) ion

• Copper(II) ion

• Lead sulfate

What is the purpose of identifying spectator ions?

• To balance the molecular equation

• To calculate the reaction rate

• To determine solubility

• To simplify the net ionic equation

What happens to the spectator ions in the net ionic equation?

• They form a precipitate

• They are removed from the equation

• They are included in the final equation

• They change their charge

What is the net charge of the products in the net ionic equation?

• 1+

• 0

• 2-

• 2+

Why is it important to balance the charges in a net ionic equation?

• To identify spectator ions

• To ensure the reaction is spontaneous

• To maintain electrical neutrality

• To increase the reaction rate