Net Ionic Equations and Solubility

The video tutorial explains how to write a balanced net ionic equation for the reaction between iron(II) sulfate (FeSO4) and sodium hydroxide (NaOH). It begins with balancing the molecular equation, followed by determining the solubility and states of the substances involved. The tutorial then breaks down the strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The video concludes by ensuring charge conservation and atom balance in the final equation.

What is the first step in writing a balanced molecular equation for a reaction?

• Identify the spectator ions.

• Determine the solubility of the compounds.

• Balance the number of atoms for each element on both sides.

• Write the net ionic equation directly.

Which of the following compounds is generally soluble in water?

• Calcium carbonate

• Sodium sulfate

• Iron(II) hydroxide

• Lead(II) chloride

What is the state of sodium hydroxide in the reaction?

• Aqueous

• Gas

• Liquid

• Solid

What is the role of a solubility table in determining the states of compounds?

• It determines the molecular weight of compounds.

• It predicts the reaction rate.

• It provides information on the solubility of compounds in water.

• It helps in identifying spectator ions.

What is the charge of the sulfate ion?

• 1+

• 1-

• 2+

• 2-

Which ions are considered spectator ions in this reaction?

• Iron(II) ions

• Hydroxide ions

• Sodium ions

• Sulfate ions

What happens to spectator ions in a net ionic equation?

• They are removed as they do not participate in the reaction.

• They form a precipitate.

• They change their charge.

• They are included in the final equation.

What is the net charge of the final net ionic equation?

• 0

• 2-

• 2+

• 1+

Why is it important to ensure that the net ionic equation is balanced?

• To make sure the reaction is spontaneous.

• To determine the reaction rate.

• To ensure the conservation of mass and charge.

• To identify the limiting reactant.

Which compound forms a solid precipitate in this reaction?

• Iron(II) sulfate

• Sodium sulfate

• Iron(II) hydroxide

• Sodium hydroxide