Net Ionic Equations and Solubility

The video tutorial explains how to write a balanced net ionic equation for the reaction between sodium sulfate and strontium nitrate. It begins with balancing the molecular equation, followed by identifying the solubility and states of the compounds involved. The tutorial then demonstrates how to split the compounds into ions to form the complete ionic equation. Finally, it shows how to derive the net ionic equation by removing spectator ions, ensuring that the charges and atoms are balanced.

What is the first step in writing a balanced net ionic equation?

• Identify spectator ions

• Write the complete ionic equation

• Balance the molecular equation

• Determine the solubility of compounds

Why is sodium sulfate considered soluble?

• It forms a precipitate

• Sodium compounds are generally soluble

• It reacts with water

• It is a gas at room temperature

Which of the following is insoluble in the reaction?

• Strontium nitrate

• Strontium sulfate

• Sodium nitrate

• Sodium sulfate

What is the charge of a sulfate ion?

• 2+

• 1-

• 1+

• 2-

In which group of the periodic table is strontium found?

• Group 4

• Group 3

• Group 2

• Group 1

What is the purpose of identifying spectator ions?

• To determine solubility

• To calculate molar mass

• To simplify the net ionic equation

• To balance the equation

Which ions are considered spectator ions in this reaction?

• Strontium and nitrate ions

• Sodium and sulfate ions

• Sodium and nitrate ions

• Strontium and sulfate ions

What is the net charge of the balanced net ionic equation?

• 0

• 2-

• 2+

• 1+

Why is it important to ensure the net ionic equation is balanced?

• To identify the limiting reactant

• To ensure conservation of mass and charge

• To predict the products

• To calculate the reaction rate

What is often placed first in net ionic equations for aesthetic reasons?

• Solids

• Positive ions

• Neutral compounds

• Negative ions