Oxidation States and Copper Compounds

The video tutorial explains how to determine the oxidation numbers for copper in copper(I) sulfate. It begins by introducing the concept of oxidation numbers and the neutrality of the compound. The sulfate ion is highlighted for its significance in chemistry, with its ionic charge of 2 minus. The tutorial then demonstrates the calculation of oxidation numbers, showing that each copper atom in Cu2SO4 has an oxidation number of plus one. The video concludes with a reference to additional resources for finding the oxidation number of sulfur in the sulfate ion.

What is the overall charge of copper(I) sulfate?

• Negative

• Variable

• Positive

• Neutral

Why can copper have different oxidation states?

• It is a non-metal

• It has a fixed oxidation state

• It is a transition metal

• It is always bonded to oxygen

What is the ionic charge of the sulfate ion?

• 2+

• 1-

• 2-

• 1+

How do oxidation numbers relate to the charge on an ion?

• They are always equal

• They are unrelated

• They add up to the charge on the ion

• They are always zero

What must the oxidation number of copper be in Cu2SO4 to balance the sulfate ion?

• -1

• +2

• 0

• +1

How many copper atoms are present in Cu2SO4?

• 1

• 2

• 3

• 4

What is the oxidation number of each copper atom in Cu2SO4?

• 0

• +1

• -1

• +2

Where can you find more information about the oxidation number of sulfur in the sulfate ion?

• In the video comments

• In the video description

• In the periodic table

• In the textbook