Oxidation Numbers and Sulfate Ions

The video tutorial explains how to find the oxidation number for chromium in chromium(II) sulfate (CrSO4). It begins by establishing that the compound is neutral, meaning the sum of oxidation numbers equals zero. The sulfate ion (SO4) is identified as having a 2- charge, which helps determine the oxidation number of chromium as +2. The tutorial also provides a link for further resources on finding the oxidation number of sulfur in the compound.

What is the overall charge of a neutral compound like chromium(II) sulfate?

• Positive

• Negative

• Zero

• Depends on the elements

What is the ionic charge of the sulfate ion (SO4)?

• 2+

• 1+

• 2-

• 1-

How do the oxidation numbers of sulfur and oxygen in sulfate relate to the ion's charge?

• They add up to 1-

• They add up to zero

• They add up to 3-

• They add up to 2-

What is the oxidation number of chromium in chromium(II) sulfate?

• +4

• +3

• +2

• +1

Why is chromium in chromium(II) sulfate referred to as chromium(II)?

• Because it has a +2 oxidation state

• Because it has a +3 oxidation state

• Because it has a +1 oxidation state

• Because it has a +4 oxidation state

Where can you find more information on finding the oxidation number of sulfur in CrSO4?

• In the video comments

• In the video thumbnail

• In the video description

• In the video title