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Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Practice Problem

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to write a balanced net ionic equation for the reaction between ammonium sulfate and barium nitrate. It begins with balancing the molecular equation, followed by determining the solubility and states of the compounds. The tutorial then demonstrates how to form the complete ionic equation by splitting strong electrolytes into ions. Spectator ions are identified and removed to derive the net ionic equation. Finally, the video verifies the balanced net ionic equation, ensuring charge and atom balance.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a balanced net ionic equation for a reaction?

Identify spectator ions

Balance the molecular equation

Determine the solubility of compounds

Write the complete ionic equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is ammonium nitrate considered soluble in water?

It reacts with water to form a gas

It forms a solid precipitate

It is a strong acid

Ammonium compounds are generally soluble

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state symbol for barium sulfate in the reaction?

(aq)

(s)

(g)

(l)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What charge does the ammonium ion carry?

2+

1+

1-

2-

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following ions is not split in the net ionic equation?

Ammonium ion

Nitrate ion

Barium ion

Barium sulfate

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of identifying spectator ions in a reaction?

To balance the equation

To calculate reaction rate

To determine solubility

To simplify the net ionic equation

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the spectator ions in the net ionic equation?

They are included in the final equation

They change their charge

They are removed from the equation

They form a new compound

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