Net Ionic Equations and Spectator Ions

The video tutorial explains how to write a balanced net ionic equation for the reaction between ammonium sulfate and barium nitrate. It begins with balancing the molecular equation, followed by determining the solubility and states of the compounds. The tutorial then demonstrates how to form the complete ionic equation by splitting strong electrolytes into ions. Spectator ions are identified and removed to derive the net ionic equation. Finally, the video verifies the balanced net ionic equation, ensuring charge and atom balance.

What is the first step in writing a balanced net ionic equation for a reaction?

• Identify spectator ions

• Balance the molecular equation

• Determine the solubility of compounds

• Write the complete ionic equation

Why is ammonium nitrate considered soluble in water?

• It reacts with water to form a gas

• It forms a solid precipitate

• It is a strong acid

• Ammonium compounds are generally soluble

What is the state symbol for barium sulfate in the reaction?

• (aq)

• (s)

• (g)

• (l)

What charge does the ammonium ion carry?

• 2+

• 1+

• 1-

• 2-

Which of the following ions is not split in the net ionic equation?

• Ammonium ion

• Nitrate ion

• Barium ion

• Barium sulfate

What is the purpose of identifying spectator ions in a reaction?

• To balance the equation

• To calculate reaction rate

• To determine solubility

• To simplify the net ionic equation

What happens to the spectator ions in the net ionic equation?

• They are included in the final equation

• They change their charge

• They are removed from the equation

• They form a new compound

What is the net charge on the reactant side of the net ionic equation?

• 1-

• 0

• 2-

• 2+

Why is it important to ensure that the net ionic equation is balanced?

• To predict the color change

• To ensure charge and mass conservation

• To determine the reaction speed

• To identify the limiting reactant

What is the final net ionic equation for the reaction between ammonium sulfate and barium nitrate?

• 2NH4+ + SO4^2- + Ba^2+ + 2NO3^- → BaSO4 + 2NH4+ + 2NO3^-

• NH4+ + NO3^- → NH4NO3

• Ba^2+ + SO4^2- → BaSO4

• Ba^2+ + 2NO3^- → Ba(NO3)2