Balancing Ionic Equations and Solubility

This video tutorial explains how to balance net ionic equations, using lead(II) acetate and ammonium bromide as examples. It covers balancing the molecular equation, determining solubility states, and forming the complete ionic equation. The tutorial concludes with deriving the net ionic equation, ensuring charge and atom balance, and highlighting the importance of understanding solubility rules and spectator ions.

What is the first step in balancing a net ionic equation?

• Split strong electrolytes into ions

• Determine the solubility of compounds

• Balance the molecular equation

• Identify spectator ions

When balancing the molecular equation, what should you do if there are two bromine atoms on one side and one on the other?

• Add a coefficient of two in front of the compound with one bromine

• Remove one bromine atom

• Do nothing

• Add a coefficient of two in front of the compound with two bromines

According to solubility rules, which of the following is generally soluble?

• Ammonium compounds

• Silver chloride

• Lead(II) bromide

• Lead(II) iodide

What does 'ss' indicate in a solubility chart?

• Soluble solution

• Slightly soluble

• Strongly soluble

• Solid state

What is the charge of the lead ion in lead(II) acetate?

• 4+

• 3+

• 2+

• 1+

Which ions are considered spectator ions in the reaction between lead(II) acetate and ammonium bromide?

• Ammonium and bromide ions

• Ammonium and acetate ions

• Lead and acetate ions

• Lead and bromide ions

What is the purpose of removing spectator ions in a net ionic equation?

• To simplify the equation

• To determine solubility

• To balance the charges

• To identify the precipitate

How is charge conservation verified in a net ionic equation?

• By checking that the net charge is zero on both sides

• By balancing the molecular equation

• By ensuring equal numbers of atoms on both sides

• By identifying spectator ions

What is the net charge on both sides of the final net ionic equation for lead(II) acetate and ammonium bromide?

• 2+

• 2-

• 1+

• 0

What is the final product in the net ionic equation for lead(II) acetate and ammonium bromide?

• Ammonium acetate

• Lead(II) bromide

• Ammonium bromide

• Lead(II) acetate