Net Ionic Equations and Spectator Ions

Net Ionic Equations and Spectator Ions

Assessment

Interactive Video

Chemistry

10th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

This video tutorial explains how to write a balanced net ionic equation for the reaction between lead(II) acetate and potassium bromide. It covers balancing the molecular equation, determining the solubility of compounds, splitting strong electrolytes into ions, and identifying spectator ions to derive the net ionic equation. The tutorial emphasizes the importance of charge conservation and atom balance in the final equation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a net ionic equation?

Determine the solubility of compounds

Balance the molecular equation

Write the complete ionic equation

Identify spectator ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we write 'aq' for acetates in the reaction?

They are gases

They are very soluble

They are slightly soluble

They are insoluble

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of lead(II) bromide in the reaction?

Aqueous

Solid

Gas

Liquid

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of a solubility table in this process?

To balance the equation

To check the solubility of compounds

To identify spectator ions

To determine the charge of ions

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What charge does the lead ion have in lead(II) acetate?

1+

2+

4+

3+

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in this reaction?

Lead and bromide ions

Only potassium ions

Only acetate ions

Potassium and acetate ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the spectator ions in the net ionic equation?

They are included in the final equation

They are removed from the equation

They form a precipitate

They change their charge

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