Oxidation States and Numbers

The video tutorial explains how to determine the oxidation numbers of elements in permanganic acid (HMnO4). It begins by identifying the compound as neutral, meaning the sum of oxidation numbers equals zero. The tutorial details the oxidation states of hydrogen and oxygen, noting hydrogen is +1 when bonded to non-metals and oxygen is typically -2. The focus then shifts to calculating the oxidation number of manganese, a transition metal, by setting up an equation based on known oxidation states. The solution reveals manganese has an oxidation number of +7, ensuring the compound's neutrality. The video concludes with a recap of the calculation process.

What is the overall charge of the compound HMnO4?

• Variable

• Neutral

• Negative

• Positive

When hydrogen is bonded to a non-metal, what is its typical oxidation state?

• +2

• +1

• 0

• -1

In acids, hydrogen is usually bonded to which element?

• Nitrogen

• Oxygen

• Carbon

• Sulfur

Why is the oxidation state of manganese in HMnO4 initially unknown?

• It is a non-metal

• It is an alkali metal

• It is a transition metal

• It is a noble gas

What is the typical oxidation state of oxygen in compounds?

• +1

• -1

• -2

• 0

How many oxygen atoms are present in HMnO4?

• 2

• 3

• 4

• 5

What equation is set up to find the oxidation number of manganese in HMnO4?

• x + 4(-1) = 0

• 1 + x + 3(-2) = 0

• 1 + x + 4(-2) = 0

• x + 4(+1) = 0

What is the oxidation number of manganese in HMnO4?

• +8

• +7

• +6

• +5

What is the sum of oxidation numbers in a neutral compound?

• +2

• -1

• +1

• 0

What is the result when you add the oxidation numbers of all elements in HMnO4?

• -1

• 0

• +2

• +1