Oxidation Numbers in Compounds

The video tutorial explains how to determine the oxidation numbers for each element in sodium cyanide (NaCN). It begins by discussing the rules for neutral compounds, where the sum of oxidation numbers equals zero. Sodium, being in group one, has an oxidation number of +1. For carbon and nitrogen, electronegativity is used to assign oxidation numbers, with nitrogen being more electronegative and having an ionic charge of -3. The oxidation number for carbon is calculated to be +2, ensuring the sum equals zero. The tutorial concludes with a recap of the oxidation numbers for NaCN.

What is the sum of oxidation numbers in a neutral compound?

• It is always positive.

• It is always negative.

• It is zero.

• It varies depending on the compound.

What is the oxidation number of sodium in NaCN?

• +2

• -1

• +1

• 0

Why can't general rules help in determining the oxidation numbers of carbon and nitrogen in NaCN?

• Because they are both non-metals.

• Because they are in the same group.

• Because they have variable oxidation states.

• Because they are both metals.

Which element is more electronegative in the CN group?

• Both have the same electronegativity

• Carbon

• Nitrogen

• Neither is electronegative

What is the ionic charge of nitrogen when it is more electronegative?

• 3+

• 2-

• 1-

• 3-

How do we denote the oxidation number of nitrogen in NaCN?

• 3+

• -3

• +3

• 3-

What equation is used to find the oxidation number of carbon in NaCN?

• 1 + x + 3 = 0

• 1 + x - 3 = 0

• x + 3 = 0

• x - 3 = 0

What is the oxidation number of carbon in NaCN?

• -2

• +2

• 0

• +3

What is the final sum of oxidation numbers in NaCN?

• -1

• +2

• 0

• +1

Who is the presenter of the oxidation numbers in NaCN?

• Dr. C

• Dr. B

• Dr. A

• Dr. D